4c^2-4c+3=2

Solution for 4c^2-4c+3=2 equation:

Simplifying
4c2 + -4c + 3 = 2

Reorder the terms:
3 + -4c + 4c2 = 2

Solving
3 + -4c + 4c2 = 2

Solving for variable 'c'.

Reorder the terms:
3 + -2 + -4c + 4c2 = 2 + -2

Combine like terms: 3 + -2 = 1
1 + -4c + 4c2 = 2 + -2

Combine like terms: 2 + -2 = 0
1 + -4c + 4c2 = 0

Factor a trinomial.
(1 + -2c)(1 + -2c) = 0

Subproblem 1
Set the factor '(1 + -2c)' equal to zero and attempt to solve:

Simplifying
1 + -2c = 0

Solving
1 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2c = 0 + -1
-2c = 0 + -1

Combine like terms: 0 + -1 = -1
-2c = -1

Divide each side by '-2'.
c = 0.5

Simplifying
c = 0.5
Subproblem 2
Set the factor '(1 + -2c)' equal to zero and attempt to solve:

Simplifying
1 + -2c = 0

Solving
1 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2c = 0 + -1
-2c = 0 + -1

Combine like terms: 0 + -1 = -1
-2c = -1

Divide each side by '-2'.
c = 0.5

Simplifying
c = 0.5
Solution
c = {0.5, 0.5}